Pole Pad
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A pole-vaulter of mass 59.8 kg vaults to a height of 5.8 m before dropping to thick padding placed below to cu?
a. Find the speed with which she lands. In m/s
b. If the padding brings her to a stop in a time of 0.50 s, what is the average force on her body due to the padding during that time interval? In N
a. Find the speed with which she lands. In m/s
59.8 x 9.8 x 5.8 = mgh (PE) = 3399.032
3399.032 = KE
KE = 1/2mv^2
3399.032/(1/2m) = v^2
= 3399.032/(0.5 x 59.8) = 113.68
sq-root(113.68) = 10.66 m/s
b. If the padding brings her to a stop in a time of 0.50 s, what is the average force on her body due to the padding during that time interval? In N
Force acting = change in momentum/ time taken for change to happen.
change in momentum = 59.8 kg x 10.66 m/s = 637.468 kg-m/s
637.468/0.5 = force acting = 1274.936 N
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